#include <stdio.h>

int main()
{
   int a = 20;
   int b = 10;
   int c = 15;
   int d = 5;
   int e;
 
   e = (a + b) * c / d;      // ( 30 * 15 ) / 5
   printf("(a + b) * c / d 的值是 %d\n",  e );

   e = ((a + b) * c) / d;    // (30 * 15 ) / 5
   printf("((a + b) * c) / d 的值是 %d\n" ,  e );

   e = (a + b) * (c / d);   // (30) * (15/5)
   printf("(a + b) * (c / d) 的值是 %d\n",  e );

   e = a + (b * c) / d;     //  20 + (150/5)
   printf("a + (b * c) / d 的值是 %d\n" ,  e );
  
   return 0;
}